Author: mostafa
•8:05 AM
Objective: Distinction between the three Dihydroxbenzene Isomers

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Chemicals:
catechol resorcinol

hydroquinone

FeCl3 · 6 H20

Solution of the dihydroxybenzenes: 0.625 g of catechol, resorcinol and hydroquinone, respectively, are dissolved in 20 mL of dist. water. The solutions should be colorless; if needed a "spatula-tip" full of charcoal is added. After shaking the suspension is filtered.
Ferric chloride solution: 1 g FeCl3 · 6 H20 are dissolved in 150 ml of dist. water.

Glass wares:
3 conical measures, graduated, 500 mL

3 glass stirring rods

beaker 200 mL

3 beakers 40 mL

3 snap-cap vials 20 mL

volumetric pipet 4 mL

volumetric pipet 10 mL

2 volumetric pipets 20 mL

1 pipette bulb

measuring cylinder 100 mL

Experimental procedure:

Three conical measures are set up as described in the following table.

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The individual dihydroxybenzene solutions are mixed with aqueous FeCl3. 4 mL of FeCl3 solution are poured into the first conical measure, 10 mL into the second measure and 20 mL into the third measure.
Results:
When treated with aqueous FeCl3, the aqueous dihydroxybenzene solutions will show the characteristic color change.


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Discussion:

Like phenol also catechol and resorcinol do form a colored complex with FeCl3.

Hydroquinone is oxidized rapidly to p-benzoquinone, which does not generate a colored complex with FeCl3.


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Redox equilibrium between hydroquinone and p-benzoquinone:


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Resorcinol shows no redox reaction with Fe3+. The two hydroxy groups in the meta position can not form a quinoid system. Thus a redox reaction between resorcinol and Fe3+ is impeded.

Catechol is only partially oxidized to o-benzoquinone.


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Author: mostafa
•11:48 PM
Objective: Electrophilic Aromatic Substitution, Acidic Azo Dyes


Chemicals :

2 N acetic acid
sulfanilic acid
ethanol 96 %

1-naphthol

2-naphthol

phenol
NaNO2
The following solutions are prepared in advance:
Phenol: 15.06 g (160 mmol) dissolved in 400 mL ethanol 96 %
1-naphthol: 17.3 g (120 mmol) dissolved in 400 mL ethanol 96 %
2-naphthol: 11.54 g (80 mmol) dissolved in 400 mL ethanol 96 %
The solutions should be colorless; if needed a "spatula-tip" full of activated charcoal powder is added. After shaking, the suspension is filtered.
Reagent solution (Diazo component): 40 mL of 0.5 % aqueous NaNO2 solution + 40 mL of 0.5 % solution of sulfanilic acid in 2 N acetic acid

Glass wares:
3 conical measures,graduated, 500 mL

3 glass stirring rods

5 beakers 50 mL

3 beakers 500 mL

graduated cylinder 200 mL

:Experimental procedure
Each of three conical measures is filled with alcoholic solutions of phenol, 2-naphthol and 1-naphthol, respectively. Afterwards the diazo component is added while stirring.

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Results:


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Discussion:

· Diazotized sulfanilic acid (1) reacts with phenol and the naphtholes forming acid azo dyes (2) The reaction proceeds according to the mechanism of electrophilic aromatic substitution.

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Author: mostafa
•1:04 AM
Objectives: Nucleophilic Carbonyl alpha-Substitution,
Test for the alpha-Methyl Carbonyl Group
Chemicals:
potassium iodide
iodine
ethanol 95%
2-propanol
acetone
2 N NaOH
Preparation of a 0.2 M iodine solution:
Using an Erlenmeyer flask, 37.35 g of potassium iodide are dissolved in 375 mL of dist. water. After the addition of 19.05 g of iodine the mixture must be stirred until it is homogeneous.
Apparatus and glass wares:
hot plate
2 thermometers
3 conical measures, graduated, 500 mL
3 glass stirring rods
Erlenmeyer flask 500 mL
3 beakers 200 mL
1 beaker 100 mL
2 pipettes 5 mL, graduated in 0.1 mL
1 pipette bulb
2 snap-cap vials 20 mL
2 measuring cylinders 200 mL
Experimental procedure:
conical measure 1: 200 ml of 0.2 M iodine solution, warmed up to 40°C
conical measure 2: 200 ml of 0.1 M iodine solution
conical measure 3: 200 ml of 0.1 M iodine solution
Iodoform test on ethanol:
60 mL of ethanol are added to the iodine solution in conical measure 1. Afterwards 150 mL of 2 N NaOH (warmed up to 40°C) are added while stirring.
Iodoform test on 2-propanol:
The iodine solution in conical measure 2 is mixed with 3.8 mL of 2-propanol and 150 mL of 2 N NaOH (room temperature).
Iodoform probe on acetone:
3.7 mL of acetone and 150 mL of 2 N NaOH (room temperature) are added to the iodine solution in conical measure 3.
Results:
A yellow, crystalline precipitate is formed in each of the three conical measures.
Discussion:
The iodoform reaction is characteristic for methylketones as well as for alcohols (e.g. ethanol, 2-propanol), that can be oxidized to a methyl carbonyl compounds. The iodoform test is a test for the existence of the CH3-CO group in a molecule. The group to which the CH3-CO group is attached can be aryl, alkyl and hydrogen.
Both ethanol and 2-propanol are oxidized by iodine to give ethanale or acetone. (1).

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When a-methyl carbonyl compounds react with iodine in the presence of a base, the hydrogen atoms on the carbon adjacent to the carbonyl group (a hydrogens) are subsituted by iodine to form tri iodo methyl carbonyl compounds which react with OH - to produce iodoform and carboxylic acid (2):

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Reaction mechanism:

The hydrogen atoms on the methyl group are slightly acidic and can be removed with hydroxide. The carbanion formed then react with iodine molecules to give a iodide ion and a monoiodonated methyl carbonyl derivate. Introduction of the first iodine atom (owing to its electronegativity) makes the remaining hydrogens of the methyl group more acidic. Hence a base-catalized iodination of a monohalogenated methyl carbonyl derivate occurs at the carbon that is already substituted. Finally a tri iodo methyl carbonyl derivate is formed.

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The next step is a nucleophilic attack by hydroxide on the carbonyl carbon atom. A carbon-carbon bond cleavage occurs and a triiodomethanide ion departs. The triiodomethanide ion is unusually stable. Its negative charge is dispersed by the three negative iodine atoms. In the last step a proton transfer takes place between carboxylic acid and triiodomethanide ion to form ultimately carboxylate ion and iodoform.

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Author: mostafa
•12:24 PM
Objectives: Nucleophilic Substitution - SN1,
Effect of the Leaving Group on Rate

Chemicals:
2-chloro-2-methylpropane 99 % (M.W. = 92.57, d = 0.851)
2-bromo-2-methylpropane 98 % (M.W. = 137.03, d = 1.221)
ethanol 96 %
0.2 % solution of bromothymol blue in EtOH 96 %
2 N NaOH
If the butyl halides are not perfectly colorless, then they must be distilled. (2-chloro-2-methylpropane, b.p. 51-52°C; 2-bromo-2-methylpropane, b.p. 73,3°C). The butyl halides should be stored in brown bottles.
Test solution:
800 mL of 96 % ethanol + 6.6 mL of 0.2 % solution of bromothymol blue in ethanol 96 % + 6.6 mL of 2 N NaOH + 200 mL of H2O
Glass wares:
2 conical measures, graduated, 500 mL
2 glass stirring rods
beaker 1500 mL
2 snap-cap vials 20 mL
2 pipettes 10 mL, graduated in 0.1 mL
2 graduated cylinder 500 mL
pipette bulb
Experimental procedure:
400 mL of the test solution heated to 60°C are poured into each of two conical measures. Then, 2-chloro-2-methylpropane is added to the solution in conical measure 2 while stirring. Afterwards the solution in conical measure 1 is mixed with 2-bromo-2-methylpropane.
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Results:
Approximately 20 seconds after the addition of 2-bromo-2-methylpropane the solution in measure 1 turns abruptly yellow. The solution of bromothymol blue in conical measure 2 remains unchanged.
Discussion:
· Bromothymol blue (transition range: pH 6.0-7.8) is an acid-base indicator that appears blue in an alkaline (base) medium, green in neutral, and yellow in an acidic solution. The solvolysis of the tertiary alkyl halides is revealed by the indicator change from blue to yellow as hydrogen halide is liberated in the reaction.
· The solvolysis of the tertiary butyl halides in water takes place by anSN1-mechamism . The reaction is unimolecular - only one species is involved in the slow step of the reaction. The reaction rate depends only on the concentration of the alkyl halide (R-X), not the nucleophile:
R = k [R-X].
In an SN1 reaction the key step is the loss of the leaving group to form the intermediate carbocation. This step is the slow, rate determining step of the reaction. The carbocation is then attacked by a nucleophile in a fast second step to form the product. The more stable the carbocation is, the easier it is to form, and the faster the SN1 reaction will be. The planar, trigonal carbocation may be attacked equally well from either side by a nucleophile. As a consequence, an SN1 reaction leads to a racemization, in which both retention and inversion of configuration at a chiral center occur to the same extent. Optically active tertiary haloalkanes produce a mixture of two enantiomers (mirror image isomers).
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· In the rate-determining step of SN1 reactions, the alkyl halide (R-X) is cleaved into a positively charged carbocation and a negatively charged leaving group. The reaction not only on the polarity of the solvent and on the stability of the carbocation, but also on the stability of the leaving group. The more stable the leaving group is, the more easily the C-X bond is also cleaved, the higher the reaction rate is. Conjugated bases of strong acids are good leaving groups. The experiment above shows that bromide ion is a better leaving group than the chloride ion. Bromide is a weaker base than chloride. Therefore the weaker base is more stable and thus more easily formed.
Relative hydrolysis rateg of R-X (R = tertiary alkyl group)
X = I > Br > Cl









Author: mostafa
•11:47 AM
Objective: Nucleophilic Substitution - SN1 and SN2
Chemicals:
1-bromobutane (M = 137.03, d =1.2785)
2-bromobutane (M = 137.03, d = 1.2585)
2-bromo-2-methylpropane (M = 137.03, d = 1.221)
bromothymol blue ethanol 99 %
0.1 N NaOH
If the butylbromides are not perfectly colorless, then they must be distilled. (1-bromobutane, b.p. 101.6°C; 2-bromobutane, b.p. 91.2°C; 2-bromo-2-methylpropane, b.p. 73.3°C). The butylbromides are to be stored in brown bottles.
Apparatus and glass wares:
heating mantle
thermometer
3 conical measures, graduated, 500 mL
3 glass stirring rods
round bottom flask 1.5 L
3 snap-cap vials 20 mL
graduated cylinder 500 mL
graduated cylinder 100 mL
volumetric pipet 2 mL
pipet ball
Experimental procedure:
The reagent solution is heated to 60°C using a heating mantle and a round bottom flask. Measured quantities of the butylbromide isomers are available in snap-cap vials:
Vial 1: 16 g of 1-bromobutane
Vial 2: 16 g of 1-bromobutane
Vial 3: 16 g of 2-bromo-2-methylpropane
300 mL of the reagent solution heated to 60°C are placed in each of three conical measures.
1-bromobutane is poured into the third conical measure while stirring with a glass rod. 2-bromobutane and tertiary butylbromide, respectively, is added with stirring to the reagent solutions in the conical measures 2 or 1, respectively.
Results:
The solution in conical measure 1 turns abruptly yellow. After some time, the solutions in the measures 2 and 3 appear green, before the color turns to yellow. 1-bromobutane (conical measure 3) reacts very slowly.
Discussion:
· Bromothymol blue (transition range: pH 6.0-7.8) is an acid-base indicator that appears blue in an alkaline (base) medium, green in neutral, and yellow in an acidic solution.
· The hydrolysis of the butyl bromide isomers is revealed by the indicator change from blue to yellow as hydrogen bromide is liberated in the reaction. The color change of the indicator permits the proof of the different reactivity of the alkyl halides. A heterolytic fission of the C-Br bond occurs. The reactivity is rising in the order 1-bromobutane <>
On the basis of mechanistical investigations can be proven:
· The hydrolysis of primary halides proceeds by an SN2-mechanism . The reaction is bimolecular, i.e. two species are involved in the rate-determining step. The reaction rate depends on both the alkyl halide's (R-X) and the nucleophile's (Nu) concentration: R = k [R-X][Nu].

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The SN2 (bimolecular nucleophilic substitution) involves rear-side attack of a nucleophile at the carbon atom, opposite to the leaving group being displaced. The incoming group replaces the leaving group in one step. Bond making and breaking occurs simultaneously. The "pentacoordinated" transition state of the SN2 reaction is a trigonal bipyramid with the nucleophile and the leaving group located at the tops of the pyramids and the three remaining substituents located at the corners of the trigonal base. As the incoming nucleophile begins to bond with the carbon, the leaving group is departing with the bonding electrons. As a result of the mechanism, the three remaining substituents are rejected. The inversion of configuration resembles the way an umbrella turns inside out in a strong gust of wind (1). If the substrate under nucleophilic attack is chiral, this leads to an inversion of stereochemistry, called the "Walden Inversion".
· The solvolysis of the tertiary butyl halides in water takes place by anSN1-mechamism . The reaction is unimolecular - only one species is involved in the slow step of the reaction. The reaction rate depends only on the concentration of the alkyl halide (R-X), not the nucleophile: R = k [R-X].

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In an SN1 reaction the key step is the loss of the leaving group to form the intermediate carbocation. This step is the slow, rate determining step of the reaction. The carbocation is then attacked by a nucleophile in a fast second step to form the product. The more stable the carbocation is, the easier it is to form, and the faster the SN1 reaction will be. The planar, trigonal carbocation may be attacked equally well from either side by a nucleophile (2).
As a consequence, an SN1 reaction leads to a racemization, in which both retention and inversion of configuration at a chiral center occur to the same extent. This effect results in a mixture of two enantiomers (mirror image isomers).
· The hydrolysis mechanism of the secondary butylbromide depends very strongly on the reaction conditions.









Author: mostafa
•8:55 PM
Objective: Nucleophilic Substitution - SN1 and SN2


Chemicals:
1-bromobutane (M.W. = 137.03, d =1.2785)
2-bromobutane (M.W. = 137.03, d = 1.2585)
2-bromo-2-methylpropane (M.W. = 137.03, d = 1.221)
ethanol 95 %
0.1 M AgNO3 solution
If the butylbromides are not perfectly colorless, then they must be distilled. (1-bromobutane, b.p. 101.6°C; 2-bromobutane, b.p. 91.2°C; 2-bromo-2-methylpropane, b.p. 73.3°C). The butylbromides are to be stored in brown bottles.
Apparatus and glass wares:
heating mantle
thermometer
3 conical measures, graduated, 500 mL
3 glass stirring rods
round bottom flask 1.5 L
3 snap-cap vials 10 mL
measuring cylinder 500 mL
measuring cylinder 25 mL
Experimental procedure:
1.2 L of ethanol are heated to 60°C using a heating mantle and a round bottom flask.
Measured quantities of the butylbromide isomers are available in sap-cap vials:
Vial 1: 8.8 g (64 mmole) 1-bromobutane
Vial 2: 8.8 g (64 mmole) 2-bromobutane
Vial 3: 8.8 g (64 mmole) 2-bromo-2-methylpropane
20 mL of aqueous 0.1 M AgNO3 solution are added to each of three conical measures containing 400 mL of ethanol heated to 60°C. 1-bromobutane is poured into the first conical measure while stirring with a glass rod. 2-bromobutane and tertiary butylbromide, respectively, is added simultaneously with stirring to the alcoholic solutions of the conical measures 2 and 3, respectively.
Results:
Reaction is indicated by the formation of a pale yellow precipitate. The tertiary halide 2-bromo-2-methylpropane immediately forms a light yellow precipitate. 2-bromobutane reacts next - a turbidity of the reaction mixture can be observed within a few of seconds. After a couple of minutes, 1-bromobutane begins to react with AgNO3 solution.




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· The rate, at which the heterolytic fission of the C-Br bond occurs, rises in the order 1-bromobutane < 2-bromobutane < tertiary butylbromide.The three reactions have the same nucleophile and the same leaving group. Hence, the rates of the SN-reactions will depend on the different structures of the butylbromide isomers.
· On the basis of mechanistical investigations can be proven: The primary halide reacts according to the SN2-mechanism (1), the tertiary halide according to the SN1-mechamism (2). The hydrolysis mechanism of the secondary butylbromide depends very strongly on the reaction conditions.


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Author: mostafa
•11:18 PM
Objectives: Nucleophilic Addition to the Carbonyl Function,

Addition-Elimination

Chemicals:
2,4-dinitrophenyl hydrazine
acetone
benzaldehyde
conc HCl
2 N HCl
Apparatus and glass wares:
2 conical measures, 350 mL
porcelain dish
beaker 800 mL
2 glass stirring rods
2 snap-cap vials 10 mL
Reagent solution:
1.2 g of 2,4-dinitrophenyl hydrazine are doused with 12 mL of conc. HCl in a porcelain dish (fume hood!). The formed light yellow hydrochloride is mixed to produce a slurry that is poured into 600 mL of 2 N HCl while stirring. The hydrochloride should be perfectly dissolved.
Experimental procedure:
Two conical measures are each filled with 300 mL of the hydrochloric acid solution of 2,4-dinitrophenyl hydrazine. 10 mL of acetone and benzaldehyde, respectively, are slowly added to the dinitrophenyl hydrazine solutions while stirring.
Results:
Copious crystalline precipitates are formed. Acetone gives a yellow precipitate and benzaldehyde gives a orange yellow precipitate.
Discussion:
The formation of this precipitate is a positive test for the carbonyl group of ketones and aldehydes. The ketone or aldehyde is converted to its hydrazone by reaction with dinitrophenyl hydrazine.
Apositive test is a yellow, orange, or red precipitate. Small crystals made from unconjugated aldehydes and ketones give precipitates toward the yellow end of the scale. Large crystals made from conjugated compounds tend to be more red.
Hydrazones have a sharp melting point and can assist in identifying carbonyl compounds.












Author: mostafa
•9:39 AM
Objective: Test for the C=C Double Bond


Chemicals:
cyclohexene
benzene
10-2 M aqueous bromine (1.28 g bromine / 800 mL H2O)
10-4 M aqueous KMnO4 (12.6 mg KMnO4 / 800 mL H2O)
Apparatus and glass wares:
4 graduated cylinders with stopper 500 mL
2 pipettes 1 mL, graduated in 0.1 mL
2 pipet bulbs
4 snap-cap vials 10 mL
Experimental procedure:
Two snap-cap vials contain 0.75 mL benzene. 0.8 mL cyclohexene are pipetted into each of two further snap-cap vials. Two collecting cylinders are each filled with 10-2 M aqueous bromine and two further cylinders are filled with 10-4 M aqueous KMnO4. The solutions are mixed with benzene and cyclohexene, respectively
The stoppered cylinders are vigorously shaken.
Results:
Benzene reacts neither with aqueous bromine nor with permanganate solution. Cyclohexene reacts with both aqueous bromine and permanganate. The solution of bromine is decolorized and purple permanganate turns brown.
Discussion:
The decolorization of bromine water is often used as a test for a carbon-carbon double bond. Bromine undergoes electrophilic addition to the double bond of alkenes. In non-aqueous solvents such as carbon tetrachloride, this gives the di-bromo product. For example, reaction with ethylene will produce 1,2-dibromoethane. When used as bromine water, the corresponding bromohydrin is formed instead.







On approaching the electron dense area of the p bond of cyclohexene, the bromine molecule becomes polarized. The electron density of the bromine is shifted, so that one bromine is partially positive and the other is partially negative charged. The Br-Br bond is heterolytically cleaved. The positively charged bromine atom acts as an electrophile, reacting with the C=C double bond. A cyclic bromonium ion is formed. The subsequent attack of the bromide ion on the three-membered ring can proceed only from the back-side, because the front-side attack is sterically hindered. The result is formation of a mixture of two enantiomeric compounds of trans-1,2-dibromocyclohexane. (1). When other nucleophiles such as water or alcohol are existing, these may attack the cyclic bromonium ion to give an alcohol or an ether (2).

Also the permanganate hydroxylation is used as a qualitative test for the presence of an alkene (Bayer test). Permanganate converts cyclohexene into a diol. In the course of the reaction purple permanganate is reduced to brown manganese dioxide (3).


Since a syn-hydroxylation takes place, the reaction is thought to involve the formation of an intermediate cyclic hypomanganate ester which is readily hydrolyzed under the reaction conditions to yield the glycol (4). Experiments with 18O-labelled permanganate demonstrate, that the two oxygen atoms of glycol originate on the permanganate and not on the solvent.







Author: mostafa
•10:09 PM
Objective: Nucleophilic Addition to the Carbonyl Function

Chemicals:
benzaldehyde
sodium disulfite

Apparatus and glass wares:
3 graduated cylinder with stopper 500 mL
beaker 200 mL
Erlenmeyer flask with stopper 250 mL
temperature probe
temperature measuring device

Experimental procedure:
Using an Erlenmeyer flask with stopper, 108 g of sodium disulfite are dissolved in 200 mL of dist. water. Sodium disulfite dissolves in water to form bisulfite ions. The solution of disulfite is poured into a graduated cylinder containing 116 mL of benzaldehyde. The stoppered cylinder is shaken vigorously. After removing the stopper a temperature probe connected to a temperature measuring device is inserted into the reaction mixture.
Results:

With an exothermic reaction the content of the graduated cylinder solidifies.
Discussion:
The characteristic reaction of aldehydes and ketones is addition across the carbon-oxygen double bond. Because of polarization of the C=O bond, the carbon atom of the carbonyl group becomes electron-deficient, acquiring a partial positive charge. This makes it susceptible to nucleophilic attack by an electron-rich chemical species. In the present case, bisulfite ion is added to the electrophilic center. Since the sulfur atom of bisulfite has an unshared pair of electrons it can act as a nucleophile and form a bond to carbonyl carbon(1)

In general, aldehydes are more reactive than ketones. There is a combination of steric hindrance and inductive effects that makes ketones to react slower than aldehydes (2).

- Bulky alkyl groups sterically hinder the approach of nucleophile.
-The electronic effects of alkyl substituents are weakly electron donating. So they make the C atom in carbonyl less electrophilic

The addition of bisulfite is usually employed to purify aldehydes. Aldehydes are isolated from reaction mixtures through its bisulfite derivatives. The addition compound can be split easily to regenerate the aldehyde by treating it with either dilute mineral acid or dilute alkali.




















Author: mostafa
•2:59 PM
Combustion Engineering
Summary :
a-Combustion :
For the combustion of 1Kg fuel a certain amount of oxygen is required .
b-Kiln gas :
The kiln gas consists of :
1-Combustion products .
2-Excess air of combustion .
3-False air .
4-Gas from raw meal .
c-Analysis of kiln gases :
The orsat-analysis is used to analyze the dry kiln gases , from orsat-analysis we get :
1-Excess air factor ( n ) .
2-Incomplete combustion .
3-Heat consumption .
4-False air .
Combustion
A-Fuel :
We have three types of fuels :
a-Gaseous fuels .
b-Liquid fuels .
c-Solid fuels .
The combustible elements that characterize fuels are carbon , hydrogen and sulfer .The complete combustion of carbon gives carbon dioxide and hydrogen gives water .The products of complete combustion of fuel are CO2 ,H2O ,N2 and O2 .The presence of CO indicates incomplete combustion .
B- Heat of combustion :
Chemical change is accompanied by absorption of heat .Heat values that generated when 1Kg of fuel is completely burned .
Purpose Of The Gas Analysis
The knowledge of the gas composition in a cement plant is important to control the firing of kiln .The following points can be determined :
1-How complete the combustion of fuel .
2-How much excess air .
3-False air .
4-Specific consumption .
Author: mostafa
•2:40 PM
Portland Cement Clinker
1 – Clinker Mineralogy .
a – The phases which should theoretically be present in a cooled clinker of this composition .
b – The quantity of each phase which should be present :
I – C3S
II – C2S
III – C3A
IV – C4AF
Phase diagram CaO-SiO2-Al2O3 .
Phase diagram CaO-SiO2-Al2O3-Fe2O3
2 – Real Clinker Minerals .
What are the real chemical compositions of the clinker minerals ?
Pure compounds C3S , C2S , C3A not occur in this simple form , but contain oxides such as MgO , Na2O , K2O , Fe2O3 and Al2O3 .
Using analytical techniques :
a – Electron microprobe analyzer .
b – Energy dispersive analyzer .
Polymorphic modification of clinker minerals
We find that not only chemical composition vary clinker minerals , but some clinker phase also exist in different polymorphic forms , which can exhibit different physical properties .
a - C3S alite
Have 6 polymorphic modification between room temperature and 11000C . The changing appear in the lattice structure .
b - C2S belite ( β-C2S ) .
Have 5 modifications between room temperature and 15000C (γ , β ,α) . The change β to γ and γ to α are irreversible and slow .
c - C3A .
C3A present as a cubic lattice , but Na2O are incorporated within the lattice forming orthorhombic , monoclinic and tetragonal modification but they differ in their reactivates .
d - C4AF .
Pure C4AF is not found .
Quantitative clinker mineralogy
A – Calculation of potential clinker composition . By Bogue , which consider chemical equilibrium has been attained .
1 – Fe2O3+Al2O3+CaO= C4AF
2 - Al2O3+CaO= C3A
3 – SO3+CaO=CaSO4
4 – CaO+SiO2= C2S
5 - C2S+CaO= C3S
6 – MgO free .
# C3S=4.07*CaO-7.6*SiO2-6.72*Al2O3-1.43*Fe2O3-2.85*SO3

#C2S=2.87*SiO2-.754*C3S
Author: mostafa
•10:33 AM
Kiln Systems
All kiln systems for burning cement clinker are based on the rotary kiln principal .
At first classification of kiln can be made according to water content of kiln feed :
1 – Dry process > 1 % water
2 – Semi-dry process 10 – 12 % water
3 – Semi-wet process 17 – 21 % water
4 – Wet process 25 – 40 % water
Dry process
Rotary kiln with :
a – four stage preheater Kilns .
Single or twin cyclone stages . The kiln exit gas use to dry raw material up to a moisture content of 8 % .
b – One or Two stage preheater kilns .
c – Shaft suspension preheater .
d – Pre-calciner Kilns .
Total fuel used in this system divided to
35 % in main burner and 65 % in pre-calciner to achieve > 90 % calcination in pre-heater .
Guidelines for choosing kiln systems
1-Production capacity and investment costs .
2-Raw material .
3-Heat economy .
4-Power consumption and pressure drop .
5-Operation and maintenance .